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3a^2/3=48a^-2/3
We move all terms to the left:
3a^2/3-(48a^-2/3)=0
We get rid of parentheses
3a^2/3-48a^+2/3=0
We multiply all the terms by the denominator
3a^2-48a^*3+2=0
Wy multiply elements
3a^2-144a+2=0
a = 3; b = -144; c = +2;
Δ = b2-4ac
Δ = -1442-4·3·2
Δ = 20712
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{20712}=\sqrt{4*5178}=\sqrt{4}*\sqrt{5178}=2\sqrt{5178}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-2\sqrt{5178}}{2*3}=\frac{144-2\sqrt{5178}}{6} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+2\sqrt{5178}}{2*3}=\frac{144+2\sqrt{5178}}{6} $
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